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golfed foofoo
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1 changed files with 25 additions and 40 deletions
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@ -153,25 +153,25 @@ lemma PolyType_0 (f : ℤ → ℤ) : (PolyType f 0) ↔ (∃ (c : ℤ), ∃ (N :
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⟨f N, by simp [(Poly_constant Poly c).mp HHH N, H1 N (le_refl N)]⟩
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cases' HHHH with d H5; exact ⟨d, by rw[← H5] at HHH; exact HHH⟩
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rcases this2 with ⟨c, hthis2⟩
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use c; use N; intro n
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constructor
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· have this4 : Polynomial.eval (n : ℚ) Poly = c := by
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use c; use N; constructor
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· intro n
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have this4 : Polynomial.eval (n : ℚ) Poly = c := by
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rw [hthis2]; simp only [map_intCast, Polynomial.eval_int_cast]
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exact fun HH1 => Iff.mp (Rat.coe_int_inj (f n) c) (by rw [←this4, H1 n HH1])
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· intro c0
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simp only [hthis2, c0, Int.cast_zero, map_zero, Polynomial.degree_zero]
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at this1
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· rintro ⟨c, N, hh⟩
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have H2 : (c : ℚ) ≠ 0 := by simp only [ne_eq, Int.cast_eq_zero]; exact (hh 0).2
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have H2 : (c : ℚ) ≠ 0 := by simp only [ne_eq, Int.cast_eq_zero, hh]
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exact ⟨Polynomial.C (c : ℚ), N, fun n Nn
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=> by rw [(hh n).1 Nn]; exact (((Poly_constant (Polynomial.C (c : ℚ))
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=> by rw [hh.1 n Nn]; exact (((Poly_constant (Polynomial.C (c : ℚ))
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(c : ℚ)).mp rfl) n).symm, by rw [Polynomial.degree_C H2]; rfl⟩
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-- Δ of 0 times preserves the function
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lemma Δ_0 (f : ℤ → ℤ) : (Δ f 0) = f := by tauto
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lemma Δ_0 (f : ℤ → ℤ) : (Δ f 0) = f := by rfl
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--simp only [Δ]
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-- Δ of 1 times decreaes the polynomial type by one
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lemma Δ_1 (f : ℤ → ℤ) (d : ℕ): d > 0 → PolyType f d → PolyType (Δ f 1) (d - 1) := by
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lemma Δ_1 (f : ℤ → ℤ) (d : ℕ): PolyType f (d + 1) → PolyType (Δ f 1) d := by
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sorry
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-- Δ of d times maps polynomial of degree d to polynomial of degree 0
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@ -181,22 +181,13 @@ lemma foofoo (d : ℕ) : (f : ℤ → ℤ) → (PolyType f d) → (PolyType (Δ
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induction' d with d hd
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· intro f h
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rw [Δ_0]
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tauto
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exact h
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· intro f hf
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have this1 : PolyType f (d + 1) := by tauto
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have this2 : PolyType (Δ f (d + 1)) 0 := by
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have this3 : PolyType (Δ f 1) d := by
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have this4 : d + 1 > 0 := by positivity
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have this5 : (d + 1) > 0 → PolyType f (d + 1) → PolyType (Δ f 1) d := Δ_1 f (d + 1)
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exact this5 this4 this1
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clear hf
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specialize hd (Δ f 1)
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have this4 : PolyType (Δ (Δ f 1) d) 0 := by tauto
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rw [Δ_1_s_equiv_Δ_s_1] at this4
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tauto
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tauto
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have this4 := hd (Δ f 1) $ (Δ_1 f d) hf
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rwa [Δ_1_s_equiv_Δ_s_1] at this4
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lemma Δ_d_PolyType_d_to_PolyType_0 (f : ℤ → ℤ) (d : ℕ): PolyType f d → PolyType (Δ f d) 0 := fun h => (foofoo d f) h
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lemma Δ_d_PolyType_d_to_PolyType_0 (f : ℤ → ℤ) (d : ℕ): PolyType f d → PolyType (Δ f d) 0 :=
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fun h => (foofoo d f) h
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lemma foofoofoo (d : ℕ) : (f : ℤ → ℤ) → (∃ (c : ℤ), ∃ (N : ℤ), (∀ (n : ℤ), N ≤ n → (Δ f d) (n) = c) ∧ c ≠ 0) → (PolyType f d) := by
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induction' d with d hd
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@ -218,13 +209,7 @@ lemma foofoofoo (d : ℕ) : (f : ℤ → ℤ) → (∃ (c : ℤ), ∃ (N : ℤ),
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sorry
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tauto
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-- [BH, 4.1.2] (a) => (b)
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-- Δ^d f (n) = c for some nonzero integer c for n >> 0 → f is of polynomial type d
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lemma a_to_b (f : ℤ → ℤ) (d : ℕ) : (∃ (c : ℤ), ∃ (N : ℤ), (∀ (n : ℤ), N ≤ n → (Δ f d) (n) = c) ∧ c ≠ 0) → PolyType f d := by
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sorry
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-- intro h
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-- intro h
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-- rcases h with ⟨c, N, hh⟩
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-- have H1 := λ n => (hh n).left
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-- have H2 := λ n => (hh n).right
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@ -242,19 +227,19 @@ lemma a_to_b (f : ℤ → ℤ) (d : ℕ) : (∃ (c : ℤ), ∃ (N : ℤ), (∀ (
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-- -- Induction step
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-- · sorry
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-- [BH, 4.1.2] (a) => (b)
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-- Δ^d f (n) = c for some nonzero integer c for n >> 0 → f is of polynomial type d
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lemma a_to_b (f : ℤ → ℤ) (d : ℕ) : (∃ (c : ℤ), ∃ (N : ℤ), (∀ (n : ℤ), N ≤ n → (Δ f d) (n) = c) ∧ c ≠ 0) → PolyType f d := by
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sorry
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-- [BH, 4.1.2] (a) <= (b)
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-- f is of polynomial type d → Δ^d f (n) = c for some nonzero integer c for n >> 0
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lemma b_to_a (f : ℤ → ℤ) (d : ℕ) : PolyType f d → (∃ (c : ℤ), ∃ (N : ℤ), (∀ (n : ℤ), N ≤ n → (Δ f d) (n) = c) ∧ c ≠ 0) := by
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intro h
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have : PolyType (Δ f d) 0 := by
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apply Δ_d_PolyType_d_to_PolyType_0
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exact h
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have this1 : (∃ (c : ℤ), ∃ (N : ℤ), (∀ (n : ℤ), (N ≤ n → (Δ f d) n = c)) ∧ c ≠ 0) := by
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rw [←PolyType_0]
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exact this
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exact this1
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end
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lemma b_to_a (f : ℤ → ℤ) (d : ℕ) (poly : PolyType f d) :
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(∃ (c : ℤ), ∃ (N : ℤ), (∀ (n : ℤ), N ≤ n → (Δ f d) (n) = c) ∧ c ≠ 0) := by
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rw [←PolyType_0]; exact Δ_d_PolyType_d_to_PolyType_0 f d poly
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end
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-- @Additive lemma of length for a SES
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-- Given a SES 0 → A → B → C → 0, then length (A) - length (B) + length (C) = 0
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section
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